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GENG2004 - Lecture 4
Generalised Hooke’s Law - Slides

Generalised Hooke’s Law

  • Normal stress causes shear strain on certain planes:
    • There must be a relationship between Young’s modulus , Poisson’s ratio and shear modulus

  • This is established through generalised Hooke’s law relationship between stress and strain in 3D (multiaxial loading)
    • Multiaxial loading application of stress in multiple directions

Assumptions:

  • Linear elasticity (no permanent deformation)
  • Small strain → see Small Deformation Theory
  • Isotropic material same properties in all directions

Given an object undergoing multiaxial loading:

  • Stress in direction → direct strain
  • Stress in and direction → still creates strain in direction
    • Think Poisson’s Ratio → lateral contraction when stretched
  • Total normal strain in direction:

  • This can be repeated for normal strain in and direction

Now for shear strain:

It is important to note:
> Normal stresses → normal strains and lateral strains (Poisson)
> Shear stresses → shear strains only

Additionally:
> Volume change (bulk behaviour)
> Shape change (shear behaviour)

All of these equations can be expressed using Einstein Notation as:

Kronecker Delta Property

The Kronecker delta () is a tool used to compare two variables. It acts as a ‘switch’ in an equation.

In the case above, for normal components and for shear components. When , delta becomes 0 (), removing the term.

Lamé Constants

Lamé constants are another way to describe the elastic behaviour of an isotropic, linear elastic material (just like our conditions above)

  • describes how normal strains in one direction influence stresses in other directions
  • (shear modulus)

These constants are useful because they make generalised Hooke’s Law more compact as seen below:

Use in Hooke’s Law:

Also used for normal stress:

Principal Axes

  • Principal directions are special directions where shear stress disappears
    • Stress becomes purely normal
  • Principal axes theorem states that for any state of stress at a point there is a set of three perpendicular axes where all shear stresses vanish
    • Calculations become much easier when shear vanishes
  • 3D questions are much harder and unlikely to be covered
    • Thus, we will focus on the method for 2D
    • This method can also be used to find maximum normal stress

Finding principal axes:

  1. Write stress matrix
  2. Use formula to solve for
  3. Rotate axes (mentally)
  4. New axes = principle axes; shear becomes zero

Principal stress formula:

  • ? Use this method when question asks for:
    • Principal stress
    • Maximum normal stress
    • Orientation/angle where shear

Material Stiffness vs Strength

  • Young’s modulus measures stiffness
    • Slope of elastic region on stress-strain curve
  • Yield stress/UCS measures strength/failure
    • UCS → Unconfined Compressive Strength

These are different material properties

  • One cannot be inferred from another
  • Stiffness strength

GENG2004 - Lecture 6