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MATH1011 - Lecture 13
Skeleton Slides

Double Integrals

  • We can use double integrals to find the volume of a surface
    • i.e. volume underneath a surface formed by
  • Region
  • We are given the double integral: (see slides)
    • If for all in , then the double integral is the volume of the solid bounded by and -plane over
      • for this example would equal
    • Order does not matter as long as the bounds match the variable

Regions Bounded By Functions: Type I

  • Let a given region be bounded by the functions
    • for all
    • The shape is enclosed by and
    • i.e. is bounded by constants and is bounded by functions of
  • The volume below over is given by the double integral:

Regions Bounded By Functions: Type II

  • Let a given region be bounded by the functions
    • for all
    • The shape is enclosed by and
    • i.e. is bounded by constants and is bounded by functions of
  • The volume below over is given by the double integral:

For regions bounded by functions, if you are trying to find area in a 2D space, set to . Example of area of eclipse on lecture recording.

Fubini’s Theorem

More Complicated Regions

  • When the region is neither type I or type II, we can usually describe is as a union of several sub-regions
  • Thus:

We will miss next Friday’s lesson, thus we are starting content early

Triple Integrals

  • The triple integral of over is:

Fubini’s Theorem Revisited

This equation is equal to all forms of its rearrangement


MATH1011 - Lecture 15
Annotated Slides